list - get keys value's from dictionary in python -

i have list of dictionary:

dictlist = [{'url': 'google.com', 'a': 10, 'content': 'google', 'd': 80, 'f': 1, 'lock': 'dd'}, {'url': 'fb.com', 'z': 25, 'content': 'google', 'd': 60, 'p': 1, 'a': 19}] 

i need create new dictionary above dictlist.

    newdict= {}     sumlist = ['a', 'z', 'd'] #get values these dictlist     dict in dictlist:         newdict['newurl'] = dict['url']         newdict['newtitle'] = dict['content']         newdict['sumvalue'] = ?????                   #so 1st item 'sumvalue'= + z + d = 10 + 0 + 80 = 90 (zero 'z')                  #and 2nd item has 'sumvalue' = + z + d = 19 + 25 + 60 = 104  print newdict[0] # should result {'newurl': 'google.com', 'newtitle': 'google', 'sumvalue' : 80 } 

i don't know how iterate through dict of dictlist sum of values list sumlist[]

i need sum of values of respective dictionary items.

please suggest.

it looks want new list of dictionaries sums inside:

dictlist = [{'url': 'google.com', 'a': 10, 'content': 'google', 'd': 80, 'f': 1, 'lock': 'dd'},              {'url': 'fb.com', 'z': 25, 'content': 'google', 'd': 60, 'p': 1, 'a': 19}]   result = [] sumlist = ['a', 'z', 'd'] d in dictlist:     result.append({'newurl': d['url'],                    'newtitle': d['content'],                    'sumvalue': sum(d.get(item, 0) item in sumlist)})  print result 

prints:

[{'newtitle': 'google', 'sumvalue': 90, 'newurl': 'google.com'},   {'newtitle': 'google', 'sumvalue': 104, 'newurl': 'fb.com'}] 

or, same in one-line:

print [{'newurl': d['url'], 'newtitle': d['content'], 'sumvalue': sum(d.get(item, 0) item in ['a', 'z', 'd'])} d in dictlist]