division - C check for number of divisors -

i trying find number of divisors each number 1 100, not understand why not working. compiler said error in line 18, 21 , 24.

#include <stdio.h> #include <math.h> #define n 100  int main() {     float n;     float l      (n=1; n<=n; n++) { //genertate list of numbers         int a;         (a=n; a>=n; a--) { //genarate list of numbers less "n"             l = n/a; //divide each number less "n"              if (l == round(l)) { //see "l" divisor of "n"                 l=l+1; //if finds divisor add                 printf(n, l); //prints number number of divisors             }         }     } } 

here warning compiler gave:

ks-macbook-pro:~ kyle$ gcc /users/kyle/app-tests/c/divisors.c /users/kyle/app-tests/c/divisors.c: in function 'main': /users/kyle/app-tests/c/divisors.c:18: error: nested functions disabled, use -fnested-functions re-enable /users/kyle/app-tests/c/divisors.c:18: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'for' /users/kyle/app-tests/c/divisors.c:21: error: 'l' undeclared (first use in function) /users/kyle/app-tests/c/divisors.c:21: error: (each undeclared identifier reported once 

/users/kyle/app-tests/c/divisors.c:21: error: each function appears in.) /users/kyle/app-tests/c/divisors.c:24: error: incompatible type argument 1 of 'printf'

float l   

missing semicolon here

printf(n, l); 

that's not how printf used, use instead:

printf("%f, %f", n, l); 

this should solve compile issue.