c - How do you declare multiple function pointers in a single line without typedeffing? -

more of matter of curiosity anything. want know if it's possible declare multiple function pointers in line, like:

int = 1, b = 2;  

with function pointers? without having resort typedef.

i've tried void (*foo = null, *bar = null)(int). unsurprisingly, didn't work.

try follows:

void (*a)(int), (*b)(int);  void test(int n) {     printf("%d\n", n); } int main() {     = null;     = test;     a(1);     b = test;     b(2);     return 0; } 

edit:

another form array of function pointers:

void (*fun[2])(int) = {null, null};  void test(int n) {     printf("%d\n",n); } int main() {     fun[0] = null;     fun[0] = test;     fun[0](1);     fun[1] = test;     fun[1](2); }