function evaluation order in C -

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this question has answer here:

#include <stdio.h>  print(int* a,int* b,int* c,int* d,int* e) {     printf("\n%d %d %d %d %d\n",*a,*b,*c,*d,*e); }  main() {     static int arr[]={97,98,99,100,101,102,103,104};     int *ptr=arr+1;     print(++ptr,ptr--,ptr,ptr++,++ptr); }

output:

100 100 100 99 100

i little confused output. because of undefined evaluation order of function or there else missing?


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