opencl - How do you read arguments passed to a native kernel? -

i have native kernel setup don't know how convert void* argument useful. in native kernel of snippet, how int (7) or int[] (16 ints set 0)?

void __stdcall nativekernel(void * args)  {     int a1 = (*(int*)args);     cout << "a1-->: "<< a1 << endl; // gibberish }   void kernelcaller()  {     const int dim1size = 16;     int dim1[dim1size] = {};      cl_int status = 0;      cl_mem mem_d1 = clcreatebuffer(*context, 0, sizeof(int)*dim1size, null, &status);     clenqueuewritebuffer(*queue, mem_d1, cl_true, 0, sizeof(int)*dim1size, dim1, 0, null, null);      const void* args[2] = {(void*)7, null};      cl_mem mem_list[1] = {mem_d1};     const void* args_mem_loc[1] = {&args[1]};      cl_event run;     status = clenqueuenativekernel(*queue, nativekernel, args, 2, 1, mem_list, args_mem_loc, 0, null, &run);     status = clenqueuereadbuffer(*queue, mem_d1, cl_true, 0, sizeof(int)*dim1size, dim1, 1, &run, null);      for(auto = 0; != dim1size; i++)         cout << dim1[i] << " "; } 

instead of playing hard void* suggest use struct create parameter structure like:

struct myparams{   int   int a[3]; }; 

and create , fill 1 struct myparams in program , pass address kernelcaller

struct myparams params; params.a=3;  status = clenqueuenativekernel(*queue, nativekernel, (void*)&params, 2, 1, mem_list, args_mem_loc, 0, null, &run); 

and in nativekernel unbox void* parameter struct:

struct myparams *params=(myparams*)args; 

beware: in example above passed pointer of stack...you might not want ;)